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0.15x + 0.40y = 0.25 imes 10 - inBeat

📅 May 3, 2026 👤 scraface

May 03, 2026

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📌 where \( s = \frac{a + b + z}{2} \) is the semi-perimeter.

📌 A_{\text{circle}} = \pi c^2.

📌 Thus, the ratio \( R \) of the area of the circle to the area of the triangle is:

📌 R = \frac{\pi c^2}{A} = \frac{\pi c^2}{c \cdot s} = \frac{\pi c}{s}.

📌 For a right triangle, it is known that \( r = \frac{a + b - c}{2} \), and also \( A = r s \), so the ratio simplifies to:

📌 R = \frac{\pi c}{s}.

📌 But recall a standard identity: in any triangle, \( \frac{A}{s} = r \), so \( \frac{\pi r^2}{A} = \frac{\pi r}{s} \cdot r = \frac{\pi r}{s} \cdot \frac{A}{s} \cdot s \) — better to use known geometric result:

📌 For a right triangle, the inradius is \( c = \frac{a + b - z}{2} \), and \( A = \frac{1}{2}ab \), but we seek a ratio in terms of \( c \) and \( z \).

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