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Home » ap classroom unit 1 progress check mcq answers ap lang - inBeat

ap classroom unit 1 progress check mcq answers ap lang - inBeat

📅 May 3, 2026 👤 scraface

May 03, 2026

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📌 Assume 1 digit = 1/8 byte → 20 digits = 20/8 = 2.5 bytes per register

📌 × 2.5 = <<10*2.5=25>>25 bytes

📌 But question asks only for ENIAC: 25

📌 But earlier step said improved to 16 binary registers (2 bytes each) → so 32

📌 But ENIAC: 25

📌 But let's match format — likely intended:

📌 ENIAC: 20 digits per register × 10 registers × (4 bits to 1 byte) → 20 × 10 × 0.5 = 100 bytes? No.

📌 Standard: 1 digit = 4 bits = 0.5 bytes → 20 digits = 10 bytes per register

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