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Home » Area of square \(= 10^2 = 100\) sq cm. - inBeat

Area of square \(= 10^2 = 100\) sq cm. - inBeat

📅 May 4, 2026 👤 scraface

May 04, 2026

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📌 Gravitational force component: \( 10 \times 9.8 \times \sin(30^\circ) = 98 \times 0.5 = 49 \, \text{N} \).

📌 Net force \( F_{\text{net}} = 50 \, \text{N} - 49 \, \text{N} = 1 \, \text{N} \).

📌 Using \( F = ma \), solve for \( a \): \( a = F_{\text{net}}/m = 1/10 = 0.1 \, \text{m/s}^2 \).

📌 #### 0.1 m/s²

📌 Find the sum of the series \( 1 + 3 + 5 + \dots + 99 \).

📌 This is an arithmetic series of odd numbers with first term \( a = 1 \), common difference \( d = 2 \), and last term \( l = 99 \).

📌 Number of terms \( n \): \( l = a + (n-1)d \rightarrow 99 = 1 + (n-1) \times 2 \).

📌 Solve: \( 98 = 2(n-1) \rightarrow n-1 = 49 \rightarrow n = 50 \).

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Perhaps the rest is 15 days, and 50% build is a distractor — no.
But since problem says 15 days, likely typo in 50% — should be 33.3% —...
Given the conflict, and for educational purpose, use the direct calcul...
The total fraction used for research and build is 20% + 50% = 70%, so...
But since the problem explicitly states the rest is 15 days, we must c...
Wait — perhaps 20% for research, and then 50% of the remainder for bui...
50% of that = 25% of total for build
Then presentation = 100% - 20% - 25% = 55%
Remaining 21 days for presentation — not 15
Only if rest is 15 days, then research and build together 30 days.

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