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📅 May 3, 2026 👤 scraface

May 03, 2026

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🔥 Popular Posts

From the cubic \( x^3 - 4x^2 + 5x - 6 = 0 \), the symmetric sums are:
\( \sum x_i = 4 \)
\( \sum_{i<j} x_i x_j = 5 \)
\sum x_i^2 = 4^2 - 2 \cdot 5 = 16 - 10 = 6
Since each \( v_i = x_i^2 \), the sum of the roots \( v_i \) is:
\sum v_i = \sum x_i^2 = 6
Therefore, the sum of the roots of the original equation is:
oxed{6}
Find the remainder when \( u^4 + 3 \) is divided by \( u^2 - 2u + 2 \)...
We are to divide \( u^4 + 3 \) by \( u^2 - 2u + 2 \) and find the rema...

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