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chronic kidney disease stage 3b - inBeat

📅 May 3, 2026 👤 scraface

May 03, 2026

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📌 So the expression becomes:

📌 \frac{b^2(x^2 + 1)}{b^2(x^2 - 1)} + \frac{b^2(x^2 - 1)}{b^2(x^2 + 1)} = \frac{x^2 + 1}{x^2 - 1} + \frac{x^2 - 1}{x^2 + 1}

📌 Let $ y = \frac{x^2 + 1}{x^2 - 1} $, then the expression becomes:

📌 y + \frac{1}{y}

📌 We compute $ y + \frac{1}{y} $. First, recall that $ x + \frac{1}{x} = 5 $. Square both sides:

📌 x^2 + 2 + \frac{1}{x^2} = 25 \Rightarrow x^2 + \frac{1}{x^2} = 23

📌 Now compute $ x^2 + 1 $ and $ x^2 - 1 $:

📌 Let $ A = x^2 + 1 $, $ B = x^2 - 1 $. Then:

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0.15x = 0.45
Divide by 0.15:
Thus, the technician needs 3 liters of the 50% saline solution.
Question: A science communicator designs an exhibit where visitors gen...
Solution: First compute $ s(4) $:
s(4) = 2(4) + 1 = 8 + 1 = 9
Now substitute $ t = 9 $ into $ b(t) $:
b(9) = 9^2 - 3(9) + 5 = 81 - 27 + 5 = 59
Therefore, $ b(s(4)) = 59 $.
\boxed{59}

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