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📅 May 3, 2026 👤 scraface

May 03, 2026

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From the identity \(\sin^2(\phi) = rac{
ho^2}{c^2}\), but express \(x^2 + y^2\) in terms of \(z\):
z = c \sin\phi \cos\phi = rac{c}{2} \sin(2\phi)
But use identity:
z =
ho \cos\phi = c \sin\phi \cos\phi = rac{c}{2} \sin(2\phi)
Alternatively, use:
ho = c \sin\phi \Rightarrow
ho^2 = c^2 \sin^2\phi
But \(

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