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📅 May 4, 2026 👤 scraface

May 04, 2026

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Try $ m = 1 $: $ x = 63(1) + 8 = 71 $
Try $ m = 2 $: $ x = 63(2) + 8 = 134 $ (too large)
Thus, the only two-digit solution is $ \boxed{71} $.
Question: What is the remainder when $ 2023 + 2025 + 2027 + 2029 $ is...
Solution: Add the numbers:
Now compute $ 8104 \mod 10 $:
\equiv 4 \pmod{10}
Thus, the remainder is $ \boxed{4} $.
Question: A science journalist is reporting on a Mars rover that sends...
Solution: The 100th signal occurs at minute:

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