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📅 May 3, 2026 👤 scraface

May 03, 2026

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Solution: Since the lines intersect at $ x = -2 $, substitute $ x = -2...
y = (2m - 1)(-2) + 3 = -2(2m - 1) + 3 = -4m + 2 + 3 = -4m + 5
y = (m + 2)(-2) - 4 = -2(m + 2) - 4 = -2m - 4 - 4 = -2m - 8
Solution: Evaluate each function at $ x = 3 $:
f(3) + g(3) = m + (-6 + 2m) = 3m - 6
Solution: Evaluate both functions at $ x = 2 $:
Evaluate $E(x)$ for each module from $x = 1$ to $x = 5$:
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