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📅 May 3, 2026 👤 scraface

May 03, 2026

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h(3) = 27 + 3(-1) + 4 = 27 - 3 + 4 = 28
e 24
Contradiction! So our assumption that \( h(x) = x^3 + px + q \) (missi...
Wait â perhaps \( h(x) = x^3 + px + q \), but we must use all three...
But let's suppose the model is \( h(x) = ax^3 + px + q \), as cubic wi...
h(1) = a(1)^3 + p(1) + q = a + p + q = 4 \quad ext{(1)}
h(2) = 8a + 2p + q = 10 \quad ext{(2)}
h(3) = 27a + 3p + q = 24 \quad ext{(3)}
Now subtract (a) from (b):
Plug into (a):

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