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Home » + \sec^2 \theta + \csc^2 \theta = 7 + \tan^2 \theta + \cot^2 \theta - inBeat

+ \sec^2 \theta + \csc^2 \theta = 7 + \tan^2 \theta + \cot^2 \theta - inBeat

📅 May 4, 2026 👤 scraface

May 04, 2026

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📌 \( x = \frac{4 \pm 4\sqrt{3}}{2} = 2 \pm 2\sqrt{3} \).

📌 Dado que \( x > 4 \), \( x = 2 + 2\sqrt{3} \approx 5.46 \).

📌 #### \( 2 + 2\sqrt{3} \)

📌 Un triángulo tiene lados de longitudes 7, 24 y 25. ¿Es un triángulo rectángulo?

📌 Verifica usando el teorema de Pitágoras: \( 7^2 + 24^2 = 49 + 576 = 625 \).

📌 Resuelve el sistema de ecuaciones: \( 2x + 3y = 7 \) y \( 4x - y = 5 \).

📌 Multiplica la segunda ecuación por 3: \( 12x - 3y = 15 \).

📌 Suma a la primera: \( 2x + 3y + 12x - 3y = 7 + 15 \).

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