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📅 May 3, 2026 👤 scraface

May 03, 2026

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Use the power rule: \(rac{d}{dx}[x^n] = nx^{n-1}\).
\(rac{d}{dx}[3x^4] = 12x^3\),
\(rac{d}{dx}[-5x^2] = -10x\),
\(rac{d}{dx}[7x] = 7\),
\(rac{d}{dx}[-9] = 0\).
The derivative is \(f'(x) = 12x^3 - 10x + 7\).
#### \(12x^3 - 10x + 7\)
Let the width be \(w\). Then the length is \(3w\).
Perimeter formula: \(2( ext{length} + ext{width}) = 64\).
\(2(3w + w) = 64\),

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Discriminant: \( 35^2 + 4Ã2Ã102 = 1225 + 816 = 2041 \)
So \( x = rac{ -35 + \sqrt{2041} }{4} \) (since \( x > 0 \))
But to match format, we write:
#### \( rac{-35 + \sqrt{2041}}{4} \)
However, due to complexity, and since the user requested difficult Oly...
The sum of the first \( n \) terms of an arithmetic sequence is given...
The sum formula: \( S_n = rac{n}{2} (2a + (n-1)d) \)
Set equal: \( rac{n}{2} (2a + (n-1)d) = 3n^2 + 5n \)
Divide both sides by \( n \) (for \( n
\( rac{1}{2} (2a + (n-1)d) = 3n + 5 \)

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