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storage units santa clarita - inBeat

📅 May 3, 2026 👤 scraface

May 03, 2026

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For $ k = -1 $: $ 1 = B(-1)(1) \implies B = -1 $.
For $ k = -2 $: $ 1 = C(-2)(-1) \implies C = \frac{1}{2} $.
\frac{1}{k(k+1)(k+2)} = \frac{1}{2k} - \frac{1}{k+1} + \frac{1}{2(k+2)...
The sum becomes:
\sum_{k=1}^{50} \left( \frac{1}{2k} - \frac{1}{k+1} + \frac{1}{2(k+2)}...
Reindex the sums:
= \frac{1}{2} \left( \sum_{k=1}^{50} \frac{1}{k} \right) - \left( \sum...
Combine terms:
= \frac{1}{2} \left( 1 + \frac{1}{2} + \sum_{k=3}^{50} \frac{1}{k} \ri...
= \frac{1}{2} + \frac{1}{4} - \frac{1}{2} - \frac{1}{51} + \frac{1}{2}...

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