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📰 But $ d(t) = t^3 $ is strictly convex and has no minimum (it decreases on $ (-\infty, 0) $, increases on $ (0, \infty) $), so it does not achieve a minimum. However, the problem states that the **minimum depth is achieved exactly once**, which implies $ d(t) $ has a unique global minimum. But $ t^3 $ has no such minimum. Contradiction? 📰 Wait — unless our initial assumption that $ d(t) = t^3 $ is forced is correct, but it violates the minimum condition. So perhaps $ d(t) $ is not exactly $ t^3 $, but fits it at four points. But a cubic is uniquely determined by four points, so $ d(t) = t^3 $ is the only cubic polynomial satisfying the conditions. 📰 But $ d(t) = t^3 $ has no minimum. Unless minimum depth refers to **local minimum**? But still, $ t^3 $ has no local minimum. 📰 Flying Bird Cat Toy 4356240 📰 Middleweight Ufc Rankings 6541383 📰 Rock Identification 1328215 📰 Bob Waterfield 6944859 📰 I Fought The Law And The Law Won 9565373 📰 Best Ai Apps For Iphone 3663327 📰 Uci California University 4178493 📰 San Sonoma 2309409 📰 From Inr To Usd In Minuteswatch Your Money Multiply Instantly 212293 📰 Hazel Maid Tv Show 1195562 📰 Grand Smokies Resort Lodge 9227843 📰 Berry Plant Related To Hawthorn 7032457 📰 Actually The Answer Is That There Are 10 Fewer Boys So The More Is Negative But In Math Contests Sometimes Signed Answers Are Accepted However In The Initial Examples All Positive 9385155 📰 Parking Work 7931728 📰 Looping Audio Converter 9540885