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Home » Substituting \(s = 6\), we have: - inBeat

Substituting \(s = 6\), we have: - inBeat

📅 May 3, 2026 👤 scraface

May 03, 2026

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📌 Reduzierter Preis = 80 $ - (15 % von 80 $) = 80 $ - 12 $ = 68 $.

📌 Endpreis nach Steuer = 68 $ + (7 % von 68 $) = 68 $ + 4,76 $ = 72,76 $.

📌 Kosten nach Anwendung des Gutscheins = 7 $ - 1 $ = 6 $.

📌 Die Diagonale eines Rechtecks misst 13 Einheiten, und eine seiner Seiten ist 5 Einheiten lang. Wie lang ist die andere Seite?

📌 This is linear in $ x $, as expected, and determines $ a $ and $ b $.

📌 But we are told $ h(x+1) - h(x) $ is linear — which is always true for quadratic polynomials, so that doesnt help distinguish. However, note: if $ h(x+1) - h(x) $ is linear, and $ h $ is quadratic, this is consistent. But we have two equations and three unknowns. But we can use the structure.

📌 Lets define $ d(x) = h(x+1) - h(x) = px + q $. Since $ h $ is quadratic, $ d(x) $ is linear. We know $ d(2024) = h(2025) - h(2024) = 2025 - 2024 = 1 $. Also, $ d(2025) = h(2026) - h(2025) $.

📌 Now, since $ d(x) $ is linear, we need another condition. But we only have two point evaluations and the form. However, we can express $ h(x) $ in terms of finite differences. For a quadratic polynomial, the second difference is constant:

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