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📅 May 3, 2026 👤 scraface

May 03, 2026

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But since \( 6x^3 = 108 \Rightarrow x^3 = 18 \Rightarrow x = \sqrt[3]{...
So the width is \( \sqrt[3]{18} \) meters.
But wait — factor:
\( 6x^3 = 108 \Rightarrow x^3 = 18 \Rightarrow x = \sqrt[3]{18} \)
Alternatively, check if integer solution: try \( x = 3 \):
\( 6(27) = 162 > 108 \)
\( x = 2 \): \( 6(8) = 48 < 108 \)
So no integer. Answer is \( \sqrt[3]{18} \), but recheck algebra.
But \( 18 = 27 \cdot \frac{2}{3} \), so no simplification.
Therefore, width is \( \sqrt[3]{18} \) meters.

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