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Home » #### \( x = 2 \), \( y = 1 \) - inBeat

#### \( x = 2 \), \( y = 1 \) - inBeat

📅 May 3, 2026 👤 scraface

May 03, 2026

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x^2 = \frac{y + 1}{y - 1}.
Since \( x^2 \geq 0 \), we require:
\frac{y + 1}{y - 1} \geq 0.
Analyzing the sign of the expression:
The numerator \( y + 1 \geq 0 \Rightarrow y \geq -1 \).
The denominator \( y - 1 > 0 \Rightarrow y > 1 \), or \( y - 1 < 0 \Ri...
Case 1: \( y > 1 \), both numerator and denominator positive.
Case 2: \( -1 \leq y < 1 \), numerator non-negative, denominator negat...
Case 3: \( y < -1 \), numerator and denominator both negative → positi...
But if \( y < -1 \), \( \frac{y+1}{y-1} > 0 \), valid. However, \( x^2...

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